In the previous figure are shown the circuits where you have to find the fdt Vo / Vi
1-2-3) Procedure: Use the voltage divider setting the numerator of the impedance which pick up the output voltage and the denominator the sum of the impedances of the circuit
4-5-6-7-8-9) Method: Using Millmann or after taking the parallel impedance output I'm a divider
10-11) Method: Using Millmann to calculate the tension between the core and the mass then use the divider to determine the output voltage
RNTS1:
Apply sequence of operations shown in Figure
Knowing Ri = 20K, Re = 0.56K, Rf = 33K, Avo = 800, Ro = RL = 4.7K and 5.6K determine aVF, Rof and Rif
and verify that AVF is close to the value 1/beta
Knowing Ri = 20K, Re = 1.2K, Rf = 33K, Avo = 800, fl = 450Hz, fh = 300KHz, Ro = RL = 4.7K and 5.6K determine aVF, FLF, fhf, Rof and Rif and verify that AvF nears a 1/beta
Knowing Ri = 20K, Re = 1.2K, Rf = 33K, Avo = 800, fl = 450Hz, fh = 300KHz, Ro = 4.7K and determining RL = 5.6K aVF, FLF, fhf, Rof and Rif and verify that AvF nears a 1/beta
Osc1:
Draw a Wien bridge oscillator that oscillates at 5kHz. The capacitors have a value of 22nF and R that connects the inverting terminal to ground is 2.2K. Determine the values \u200b\u200bof other R.
Draw a Wien bridge oscillator, knowing that C = 10nF and R = 4.7K, while the R that connects the output to the inverting terminal is 6.8K. Finding the oscillation frequency and the other R.
Method: Simply open the ring on the operational +, calculate and A beta in literal form using the complex frequency s, set aside the real part of the denominator of the beta so that beta becomes real and its reciprocal is calculated the value of A and then the resistance values.
Osc2:
In opening the ring oscillator is estimated that the beta is given by the expression 2RCS / [(RCS) RCS +6 ^ 2 + 3] with C = 10nF and R = 2.2K. Finding the oscillation frequency and the minimum value of A necessary for its operation
Procedure: w to simply cancel the real part of the denominator of beta and, once made, should be reversed to find
Osc4: Given a Colpitts oscillator in where the amplification is -8 C and output swings 100Khz 2nF knowing that determine the value of L and the input capacitor.
Osc5: Given a Hartley oscillator where L1 = L2 = 2.2uH 1UH and find the frequency of oscillation and amplification, knowing that the value of C = 100pF
Procedure: we always here from the theorem of the three points, writing the expressions of the impedance is calculated by writing we are beta then calculates A.
Osc6: Given a phase shift oscillator in which C = 10nF and R = 2.2K find the minimum amplification and oscillation frequency.
Procedure: beta = (RCS) ^ 3 / [(RCS) ^ 3 +6 (RCS) RCS ^ 2 +5 +1] for which cancels the real part of the denominator we find for inverting the value of beta is
Osc7: Designing with NE555 astable where f = 4 kHz and the DC is 60%
Procedure: Based on the scheme chosen are the time constants of charging and discharging, with these are the times when the pulse remains high and low.
Osc7: Repeat with DC 25%
Osc8: Design an astable with OA so that f = 5kHz and the DC is 50% at Vcc = 18V.
Procedure: Based on the scheme chosen are the time constants of charging and discharging, with these are the times when the momentum is high and low.
Osc9: Repeat with DC 25% and 70%
Osc10: Design a monostable with OA, complete control circuit, which produces an output pulse of 3ms, with Vcc = 18V. Also means the minimum value of the square wave frequency used for switching.
Osc11: Design a monostable with NE555, complete control circuit, which produces an output pulse of 3ms. Also means the minimum value of the square wave frequency used for switching.
Osc12: Design a triangular wave generator that produces a maximum voltage of 10V at a frequency of 3 KHz with Vcc = 18V.
For the filters we must remember the formulas from which to obtain the design parameters:
Low pass:
A (s) = Ao / [(s ^ 2 / w ^ 2) +2 z (s / w) + 1] (fdt general)
A (s) = K / [(RCS) ^ 2 + (3-k) +1 RCS] with K = 1 + Ra / Rb (FDT specification filter VCVS)
High Pass :
A (s) = Ao (s / w) ^ 2 / [(s ^ 2 / w ^ 2) +2 z (s / w) +1]
A (s) = K (RCS) ^ 2 / [(RCS) ^ 2 + (3-k) +1 RCS] with K = 1 + Ra / Rb
Band Pass:
A (s) = 2zAo (s / w) / [(s ^ 2 / w ^ 2) +2 z (s / w) +1]
A (s) = K (RCS) / [(RCS) ^ 2 + (4-k) +2 RCS] with K = 1 + Ra / Rb
NB The values \u200b\u200bof z F necessary for the projects are located in tables in the book
The way to proceed in doing the exercises when designing a filter is this:
1) schematic contrasseganto the names of the components to be determined
2) to determine the relationship between filter parameters (w, z, Ao) and the values \u200b\u200bof circuit components (the various R and C circuit) from the comparison between the FDT general and specific circuit
3) if necessary to find values \u200b\u200bin the table design of the filter (F z) and so the natural fo
4) calculate the R and C of the circuit design
Filtr1: Designing a filter of the first order low-pass amplification of 3 and ft = 2 KHz
Filtr2: Designing a filter of the first order high-pass amplification of 2.5 and ft = 5kHz
Filtr3: Designing a filter of the first order high-pass amplification of 4dB and ft = 1KHz
Filtr4: Design a second order filter of the second lowpass Butterwotrh and ft = 5kHz
Filtr5: Design a second order filter of the second lowpass Butterwotrh with amplification and ft = 5dB 3KHz
Filtr6: Design a second order filter of the second highpass Butterwotrh amplification of 2.5 and ft = 4KHz
Filtr7: Designing a filter of the II order lowpass Chebyshev with ft = 4KHz
Filtr8: Design a filter II order highpass Chebyshev with ft = 3KHz
Filtr9: Design a second order filter of the second highpass Chebyshev with ft = 3 KHz and gain 6dB
Filtr10: Designing a filter of the II order lowpass Bessel ft = 3 KHz
Filtr11: Designing a filter of the II order lowpass Bessel ft = 3 KHz with a gain of 8dB
Filtr12: Designing a filter of the third order lowpass Butterworth ft = 3 KHz 4dB gain and
Filtr13: Designing a filter of the third order highpass Butterworth ft = 4 kHz and gain 4dB
Filtr14: Designing a filter of the third order lowpass Chebyshev with ft = 4 kHz and gain 4dB
Filtr15 : Designing a filter of the third order highpass Bessel ft = 4 kHz and gain 4dB
Filtr20: Design a bandpass filter (narrow band) for = 4 kHz and gain 4dB
Filtr21: Design a bandpass filter ( narrowband) for = 4 kHz and Q = 5
Filtr22: Design a bandpass filter (narrow band) and for = 5kHz bandwidth of 2 kHz
Filtr23: Design a two-stage bandpass filter (bandwidth close) with for = 4kHz and Q = 5
Filtr30: Design a bandpass filter in broadband (the II order) with fl = fh = 12KHz and 1KHz
Filtr31: Design a bandpass filter in broadband (the II order) in two stages with fl = 1kHz and 12kHz bandwidth
Filtr40: Designing an Exclude filter bandwidth (narrow band) with for = Q = 3 and 3Khz
Filtr41: Designing an Exclude filter bandwidth (in narrowband) with B = for = 5kHz 2kHz
Filtr42: Designing an Exclude filter bandwidth (high bandwidth) with fl = B = 1kHz and 10kHz
Filtr43: Designing an Exclude filter bandwidth (high bandwidth) with fl = fh = 1kHz and 11kHz
to Remember power, the following definitions disting the static variables from those dynamics: CCP, PD, PL, Vceq, Icq, Pu, F, age, or THD Dtot, Icm, Vcem, VLM and ILM
The exercises are performed using the stylized graphic technical prescriptions of the output to identify the location of the rest.
Once you have determined the point of rest diseganrela static and dynamic load line, and then determine the value vcem that the point of rest are discussing cuts without distortion or
POT1: Find the rest point of a BJT which supplies a load Rc current path from Vcc = 12V, Rc = 8 Ohm, Beta = 40, RB = 0.5K and the maximum value for the oscillation whereas Vcesat = 0V. Also calculate PD, PL, F and age.
POT2: Find the rest point of a BJT which supplies a load current flowing Rc with Vcc = 15V, Rc = 8 Ohm, Beta = 50, RB = 0.82K, and the maximum value for the oscillation whereas Vcesat = 1.5 V. Also calculate PD, PL, F and age.
Pot3: Find the rest point of a BJT which supplies a load current flowing Rc with Vcc = 15V, 8 Ohm = Rc, Re = 1ohm, Beta = 80, RB = 0.56K, and the maximum value for the oscillation Whereas Vcesat = 1V. Also calculate PD, PL, F and age.
Pot4: Find the rest point of a BJT which supplies a load current flowing Rc with Vcc = 15V, Rc = 4 Ohm, Re = 2Ohm, Beta = 80, RB = 0.56K, and the maximum value for the oscillation Whereas Vcesat = 1V. Also calculate PD, PL, F and age.
Pot5: Find the rest point of a BJT feeding an RL load current path from Vcc = 15V, RL = 4 Ohm, Re = 0Ohm, Beta = 80, RB = 0.56K, and the maximum value for the ' Whereas oscillation Vcesat = 0V. Also calculate PD, PL, F and age.
Pot6: Find the rest point of a BJT feeding an RL load current path from Vcc = 15V, RL = 4 Ohm, Re = 2Ohm, Beta = 80, RB = 0.56K, and the maximum value for the ' Whereas oscillation Vcesat = 1V. Also calculate PD, PL, F and age.
Pot10: Find the rest point of a BJT feeding an RL load with a transformer coupled with Vcc = 15V, RL = 4 Ohm, n = 2, Beta = 80, RB = 0.56K and maximum value for the oscillation whereas Vcesat = 1V. Also calculate PD, PL, F and age.
Pot11: Find the rest point of a BJT feeding an RL load with a transformer coupled with Vcc = 15V, RL = 8 Ohms, n = 3.2, Re = 2Ohm, Beta = 80, RB = 0.56K and value whereas the maximum oscillation Vcesat = 1V. Also calculate PD, PL, F and age.
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